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Networking

    • 14 posts
    August 13, 2018 12:09 PM PDT

    Can anyone solve this? ;) 

    Your router has the following IP address on Ethernet0: 172.16.2.1/23. Which of the following can be valid host IDs on the LAN interface attached to the router?

    • 11 posts
    August 14, 2018 9:00 AM PDT

    Noshin, is this sort of like multiple choice questions?  Give me some hints..   :)

    • 14 posts
    August 14, 2018 9:09 AM PDT
    no actually it's not multiple choices, you have to find out by doing mathematics
  • August 14, 2018 11:35 AM PDT

    172.16.2.255

    172.16.3.0

    The router's IP address on the E0 interface is 172.16.2.1/23, which is 255.255.254.0. This makes the third octet a block size of 2. The router's interface is in the 2.0 subnet, and the broadcast address is 3.255 because the next subnet is 4.0. The valid host range is 2.1 through 3.254. The router is using the first valid host address in the range.

    • 11 posts
    August 14, 2018 1:04 PM PDT

    Thanks for the response Nissan. 

     

    I see...so Noshin where did you get this question? ;)

     

     

    • 11 posts
    August 14, 2018 1:04 PM PDT

    Very tricky! :)

    • 14 posts
    August 15, 2018 7:47 AM PDT

    I got this question from Indiabix.com. Actually, i want to do math, not explanation. How can you find out the answer ;)

    • 11 posts
    August 15, 2018 9:01 AM PDT

    I am not sure either :) Can you share? 

    • 14 posts
    August 15, 2018 9:10 AM PDT

    In the FB page i have to share??

    • 11 posts
    August 15, 2018 9:41 AM PDT

    No, you can post here. I am curious myself :)

    • 1 posts
    March 22, 2019 1:35 AM PDT
    Hi